Phthalic Anhydride derived Polyesters and Nylon structures+reactions?

  • Thread starter Thread starter ptpatil
  • Start date Start date
AI Thread Summary
Phthalic anhydride reacts with ethylene glycol to form a polyester through a condensation reaction, where hydroxyl groups from the glycol react with the anhydride, releasing water. Glycerin can also react similarly to produce a different polyester structure. Nylon is synthesized from sebacoyl chloride and hexamethylenediamine, involving a similar condensation mechanism that forms amide linkages. Understanding the specific structures of these polymers requires knowledge of their chemical reactions and the resulting polymer chain configurations. Further study of these reactions will clarify the polymer structures and their properties.
ptpatil
Messages
6
Reaction score
0
Phthalic Anhydride derived Polyesters and Nylon structures+reactions?

Homework Statement


Im doing a lab for Materials science for engineers.
they want to know how phthalic anhydride and ethylene glycol makes a polyester. They also want to know how that and glycerin make a polyester.

After that we made nylon from sebacoyl chloride and hexamethylenediamine.

Im a first year student and I have no clue how these reactions work, they didnt teach us about the chemistry just the mechanical properties once the polymer chains are formed.

Homework Equations


Phtalic anhydride:
100px-Phthalic_anhydride.png


ethylene glycol:glycerin:
Glycerin.gif


sebacoyl chloride:
111-19-3.gif


hexamethylenediamine:

The Attempt at a Solution



I figured that the OHs would probably react with each other on the ends of the molecule but I have no idea what the polyester structure would be of the either the phthalic anhydride derived polyesters or the nylon-6,10.

I do know that there are probably two reactions from the ethylene glycol with the oxygens in the phthalic anhydride but nothing further than that.
 
Last edited by a moderator:
Physics news on Phys.org


oops the pictures for the different chemicals don't work, ill try and fix it
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...

Similar threads

Back
Top