Phys 1301: Dropping Chestnuts from a Tree Branch

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To determine the initial speed required for the second chestnut to reach the ground simultaneously with the first, the relevant equations of motion must be applied. The first chestnut falls from a height of 11 meters, having fallen 2.3 meters when the second chestnut is thrown. The time taken for the first chestnut to fall 2.3 meters can be calculated using the equation of motion, allowing for the determination of the time remaining for the first chestnut to hit the ground. This time can then be used to calculate the necessary initial speed for the second chestnut, which is thrown from a height of 8.7 meters. The problem requires careful application of kinematic equations to ensure both chestnuts land simultaneously.
ramancer
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While sitting on a tree branch 11 above the ground, you drop a chestnut. When the chestnut has fallen 2.3 , you throw a second chestnut straight down

What initial speed must you give the second chestnut if they are both to reach the ground at the same time?
 
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Adding units to your values would be nice. I reckon you mean 11 and 2.3 meters? Which equations do you think are relevant to this problem?
 

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