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Hybr!d
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[SOLVED] Physic Question
Calculate the location of the center of mass of the Earth-Moon-Sun system during a full Moon. A full Moon occurs when the Earth, Moon, and Sun are lined up as shown in the figure. Use a coordinate system in which the center of the sun is at x=0 and the Earth and Moon both lie along the positive x direction.
The mass of the Moon is 7.35×10^22 kg, the mass of the Earth is 6.00×10^24 kg, and the mass of the sun is 2.00×10^30 kg. The distance between the Moon and the Earth is 3.80×10^5 km. The distance between the Earth and the Sun is 1.50×10^8 km.
I am using the x(cm) = m1x1 + m2x2 + m3x3/ m1 + m2 + m3
Where m is masses of the objects and x is distance
I put in x(cm) = ((2.00 x 10^30)(1.50×10^8 km) + (7.35×10^22 kg)(3.80×10^5 km) + (6.00×10^24 kg)(1.50×10^8 km))/(7.35×10^22 kg + 6.00×10^24 kg + 2.00×10^30 kg)
I know I am subbing in the wrong value somewhere.
Homework Statement
Calculate the location of the center of mass of the Earth-Moon-Sun system during a full Moon. A full Moon occurs when the Earth, Moon, and Sun are lined up as shown in the figure. Use a coordinate system in which the center of the sun is at x=0 and the Earth and Moon both lie along the positive x direction.
The mass of the Moon is 7.35×10^22 kg, the mass of the Earth is 6.00×10^24 kg, and the mass of the sun is 2.00×10^30 kg. The distance between the Moon and the Earth is 3.80×10^5 km. The distance between the Earth and the Sun is 1.50×10^8 km.
Homework Equations
I am using the x(cm) = m1x1 + m2x2 + m3x3/ m1 + m2 + m3
Where m is masses of the objects and x is distance
The Attempt at a Solution
I put in x(cm) = ((2.00 x 10^30)(1.50×10^8 km) + (7.35×10^22 kg)(3.80×10^5 km) + (6.00×10^24 kg)(1.50×10^8 km))/(7.35×10^22 kg + 6.00×10^24 kg + 2.00×10^30 kg)
I know I am subbing in the wrong value somewhere.
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