An electron moving along the x axis has a position given by x = 18te^-1t m, where t is in seconds. How far is the electron from the origin when it momentarily stops
Obviously v(t) = x'(t) so differientiation of x(t) is necessary to find v(t)=0.
From this, we can plug t into x(t) to calculate the position of the electron when the particle momentarily stops [v(t)=0].
The Attempt at a Solution
However, I am unfamiliar in dealing with vairables in exponents.
I tried to calculate x'(t) and got: -18t^2 e^-2t.
I'm pretty sure this calculation is wrong and if its not, I'm very sure I don't know how to solve x'(t) = 0!!