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## Homework Statement

An electron moving along the x-axis has a position given by x = 18te^-1t m, where t is in seconds. How far is the electron from the origin when it momentarily stops

## Homework Equations

Obviously v(t) = x'(t) so differientiation of x(t) is necessary to find v(t)=0.

From this, we can plug t into x(t) to calculate the position of the electron when the particle momentarily stops [v(t)=0].

## The Attempt at a Solution

However, I am unfamiliar in dealing with vairables in exponents.

I tried to calculate x'(t) and got: -18t^2 e^-2t.

I'm pretty sure this calculation is wrong and if its not, I'm very sure I don't know how to solve x'(t) = 0!

help?

thanks