Physics banking problems w\ friction.

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A 1200-kg car is rounding a banked curve with a radius of 70m at a speed of 90 km/h (25 m/s) and an angle of 12 degrees. The calculations show that a coefficient of friction of 0.72 is necessary to maintain the car's trajectory. The force of friction acts perpendicular to the normal force. While the solution is mostly correct, it lacks an explanation of why friction is needed in this scenario. Understanding the role of friction is crucial for accurately solving banking problems in physics.
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Homework Statement



A 1200-kg car rounds a curve of radius 70m banked at an angle of 12 degrees. If the car is traveling at 90km/h, will friction force be required? If so, how much and in which direction?

Homework Equations



mv^2/r = Fc

The Attempt at a Solution


90km/h = 25m/s

Fc = Fnx + uFny
mv^2/r = mgsin12 + u9.8cos12

25^2 = 9.8sin12 + u9.8cos12

u=.72; The coefficient of friction .72 and the force of friction will be perpendicular to the normal force.

Can someone confirm that this is the correct answer?
 
Last edited:
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You have a few errors in writing it out, but your answer is correct. You have not explained why friction is required.

AM
 

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