Physics Centripetal Force problem?

AI Thread Summary
To create a gravity equal to 0.7 times that of Earth's at a space station with a 200m diameter, it must rotate at a linear speed of 26.2 m/s, resulting in a complete rotation period of 24 seconds. The calculations for linear speed and rotation period are confirmed to be correct. If angular speed is required, it can be calculated as approximately 0.262 rad/sec. This value is derived from both the period of rotation and the relationship between linear speed and radius. The discussion clarifies the distinction between linear and angular speed in the context of centripetal force.
Brij Patel
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1. At what rate a space station 200m in diameter would have to rotate to create gravity equal to 0.7 that at the surface of earth. How fast does it spin, and how long would it take to make a complete rotation? 2. a2 = v2 / 100m
T = 2pi(r) / v

3.
so far: 6.867m/s2 = v2 / 100m = 26.2 m/s

T = 2pi(100) / 26.2m/s = 24 sec

did I do it right?
 
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Welcome to PF!

Your work looks good. The phrase "how fast does it spin" might refer to angular speed rather than linear speed at the outer rim.
 
TSny said:
Welcome to PF!

Your work looks good. The phrase "how fast does it spin" might refer to angular speed rather than linear speed at the outer rim.
The problem is word for word so I assume they're asking for angular speed.
Am I correct, though?
 
If they're asking for angular speed, then you need to calculate the angular speed. I believe your answers for the linear speed and period of rotation are correct.
 
TSny said:
If they're asking for angular speed, then you need to calculate the angular speed. I believe your answers for the linear speed and period of rotation are correct.
w = 2pi / T
w = 2pi / 24 = .2618 rad/sec
is that correct?
 
Yes. It's also v/r = 26.2/100=0.262 rad/sec
 
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