Physics help please determining distance of box pushed

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A 20kg block is pushed with an 8N force, reaching a final speed of 2 m/s, and the goal is to determine the distance it was pushed. The initial attempt calculated the distance as 10m but was deemed incorrect. To solve the problem accurately, the kinematic equation Vf^2 - Vo^2 = 2*a*displacement should be used, assuming a frictionless surface. The correct approach involves calculating acceleration first, then using the known final and initial velocities to find the displacement. This method will yield the accurate distance the box was pushed.
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Homework Statement


A block has a mass of 20kg is at rest on the floor. This block is then pushed by a horizontal force of 8N across the floor. The final speed is 2 m/s. Determine the distance the box was pushed.


Homework Equations


Fnet=ma
d=(t)(s)
a=(chand in velocity)/(change in time)


The Attempt at a Solution


Using all three equations I found the distance to be 10m. But this answer is incorrect. I can't figure out what I am doing wrong.
 
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lbella026 said:

Homework Statement


A block has a mass of 20kg is at rest on the floor. This block is then pushed by a horizontal force of 8N across the floor. The final speed is 2 m/s. Determine the distance the box was pushed.


Homework Equations


Fnet=ma
d=(t)(s)
a=(chand in velocity)/(change in time)


The Attempt at a Solution


Using all three equations I found the distance to be 10m. But this answer is incorrect. I can't figure out what I am doing wrong.

have you used the kinematic equation Vf^2 - Vo^2 = 2*a*displacement ?

I think you figured out acceleration a, properly...(assume we have a frictionless surface). So if you know a, Vf and Vo, you can figure out displacement (or distance the box moved).
 
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