Mastering Motion of 2 Dimensions in Physics - Solved Problem and Techniques

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The discussion focuses on solving a Grade 12 Advanced Placement Physics problem involving the motion of a ball thrown from a hot-air balloon. The user is seeking clarification on using the "Component Technique" for two-dimensional motion, as they are more familiar with the Sine and Cosine laws. They present a sample problem where a ball accelerates downward, and its final velocity is given at a 45-degree angle. The calculations reveal that the horizontal and vertical components of the final velocity are equal, leading to the determination of the initial speed. The final result for the initial speed of the ball is calculated to be approximately 17.17 m/s.
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[SOLVED] Physics - HELP!

Hey guys,

Currently taking Grade 12 Advanced Placement Physics. I'm craming for a kinetics test tomorrow, which I will do reasonably well. However, I am still stumped on solving Motion of 2 Dimensions using the "Component Technique". I am able solve it using the Sine and Cosine laws, but I have to be able to solve it using both.

If anyone could help me out by taking a shot at explaining it, it would be very much appreicated.

A sample problem:

A passenger in a hot-air balloon throws a ball with an initial unknown velocity. The ball accelerates at 9.8m/s/s [down] for 2.0s, at which time its instantaneious velocity is 24m/s [45 degrees below the horizontal]. Determine the ball's initial velocity.

Again, any help would be greatly appreciated.
 
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After 2 seconds,
Vx^2 + Vy^2 = 24^2

With the 45 degree angle thing, conclude Vx = Vy at this time

Vx = (576/2)^0.5
= 16.97ms-1
Vy = 16.97ms-1

Assume horizontal velocity unchanged over 2s. Ux = Vx = 16.97ms-1

Uy = Vy - 9.81*2
= - 2.63ms-1

Note: 'U' refers to initial velocities, 'V' to end ones, 'x' to horizontal direction, 'y' to vertical.

Initial speed = 17.17ms-1
 
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