Physics II Lab - Fizeau's Experiment - Speed of Light

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Homework Help Overview

The discussion revolves around Fizeau's experiment to measure the speed of light, focusing on the relationship between distance, frequency, and the mechanics of a rotating toothed wheel. Participants are exploring how to calculate the speed of light using experimental data, including a distance of 17.3 km and a frequency of 2200 Hz.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to apply the speed of light formula, questioning whether the values used are appropriate. There is discussion about the need for additional context regarding wavelength and frequency, as well as the mechanics of the experiment. Some participants suggest focusing on time, speed, and distance rather than wavelength.

Discussion Status

Several participants have provided insights into the calculations and the underlying principles of the experiment. There is a mix of interpretations regarding the correct approach to derive the speed of light, with some suggesting a specific equation derived from the experiment's setup. No explicit consensus has been reached, but productive lines of reasoning are being explored.

Contextual Notes

Participants note that the original lab instructions do not provide explicit information about wavelengths or frequencies, leading to some confusion. The discussion includes assumptions about the nature of the light used and the mechanics of the toothed wheel.

dmullin4
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Homework Statement


I know that the light wave must travel 17.3 km or 17300 meters.
I found experimentally that the frequency should be 2200 Hz. I picked it from a pool ranging from 0 Hz to 5600 Hz. The goal was to see what frequency was required to get the light to pass correctly through a gap in a wheel.

I am asked to use the data gathered to calculate "your speed of light."


Homework Equations


speed of light = wavelength * frequency
c = (lambda)*f


The Attempt at a Solution


I am assuming it is supposed to be around the actual speed of light which is 2.99x10^8 m/s. I am getting a value of 3.806x10^7 m/s by multiplying 17300 m by 2200 Hz.

Am I using the wrong values? Is there some constant I am overlooking that I need to throw in? Is there another equation?
 
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You are assuming that the wavelength of the light is 17.3 km... does that make sense?

I think you might need to describe the context of this question in more detail.
 
Here is the information page from the lab experiment. There is nothing mentioned about wavelengths or frequencies, except what I figured out that the wheel needs to turn at 2200 rev/s.

Fizeau’s experiment
A light source sends a beam of light toward a partially silvered mirror. The partially silvered mirror splits the light beam, so part of the beam is reflected perpendicular to its original direction and heads outward (to the right). This outward beam passes through one of the gaps in a rotating toothed wheel, hits a flat mirror, and is reflected back towards the wheel. If the wheel is rotating at the right speed, the reflected beam can pass back through a gap in the wheel to be seen by the observer.

Although Fizeau’s original experiment used a toothed wheel with 720 gaps, this animation only used 8 gaps. The round-trip distance from the wheel to the flat mirror and back again is 17.3 km, the same as in Fizeau’s setup. Can you use Fizeau’s experiment to determine the speed of light?
 
It is not wavelength/frequency problem, it is simple time, speed, distance.
 
Ok, so I have the distance. Where do I get the time and speed? Its a red light, so I know that's a specific wavelength, but will it be similar to the speed of light at 2.99x10^8 m/s?
 
Thank God for Youtube.

I found an equation off a video of Fizeau's experiment on Youtube that gave me the equation:

v = 2*d*N*f

which is velocity = 2 * distance between mirrors * number of teeth on wheel * frequency

Plugging all this in, I got 3.04x10^8 which is pretty darn close to the speed of light. At least I'm not off by a magnitude of 10!
 
I think it is faster to derive this equation from known data, than to google it. For the light to get through time it spends traveling to mirror and back must be identical to the time needed for next teeth (or rater slot between) to come to the same place. N*f is just a frequency at which the slots appear in the same position - and 1/(N*f) is a period. If light passes through it means it made 2*d in one period, so total distance traveled in 1 sec is 2*d*N*f.
 

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