Physics Midterm: Calculate Electric Field at Origin

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To calculate the net electric field at the origin due to two point charges, the electric fields generated by each charge must be determined using the formula E = kq/r^2. The charge Qa, a -5.00 microcoulomb charge located 3 meters above the origin, produces an electric field of -5000 N/m, while the charge Qb, an 8.00 microcoulomb charge located 4 meters to the right, generates an electric field of 4500 N/m. The next step involves combining these vector components, which can be achieved using the Pythagorean theorem to find the magnitude of the resultant electric field. This approach ensures that the direction and magnitude of the electric fields from both charges are accurately accounted for. Understanding these principles is crucial for solving similar problems in electrostatics.
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Homework Statement



A two point charges (Qa and Qb) are placed along the y and x axis, as shown below:

The Qa charge is placed 3 meters up from the y axis, which contains a -5.00 microcolumb charge. The Qb charge is placed 4 meters away from the x axis, which contains a 8.00 microcolumb charge.

a. Calculate the net electric Field at the origin.

Homework Equations



E-Field on Qa = kq/r^2
E-Field on Qb = kq/r^2[c]3. Attempt of a solution[/b]E-Field on Qa = kq/r^2 = (9.0 E9 N m^2/C^2)(-5.00 E-6 C)/(3m)^2 = -5000 N/m
E-Field on Qb = kq/r^2 = (9.0 E9 N m^2C^2)(8.00 E-6 C)/(4m)^2 = 4500 N/m

Where do I go from here? Do I add the E-Fields or Find the Pythagorean Theorem to find the magnitude of the E-Field?

Thanks.

BTW...Dont worry I am not cheating...IM just asking a question that was asked on the midterm...that I didnt get the answer from.
 
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The E-field is a vector field.

So accounting for the contribution from the 2 charges means adding the vector components.

Looks like Pythagoras would be the way to go to calculate |E|.
 
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