Physics Problem: Calculating Velocity of a Thrown Ball at State Fair Booth

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The discussion revolves around calculating the final velocity of a thrown ball after an elastic collision with a bottle. The initial momentum of the ball is determined to be 10.5 kg·m/s, while the final momentum of the bottle is calculated as 6 kg·m/s. Using the conservation of momentum principle, the equation (0.5)(21) = (0.2)(30) + (0.5)(final speed of ball) is established. The calculation leads to a final speed of the ball being 9 m/s. The conclusion is that the final velocity of the ball after hitting the bottle is indeed 9 m/s.
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ok here the question:
jamal is at the state fair playing some of the games. at one booth he throws a 0.50-kg ball forward woth a velocity of 21.0 m/s in order to hit a 0.20-kg bottle sitting on a shelf, and when he makes contact the bottle goes flying forward at 30-0 m/s.

A) What is the velocity of the ball after it hits the bottle?
 
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so we assume its an elastic collision. which means momentum and energy are conserved. but since you have the end speed of the bottle we won't need energy.

so we know that the intial momentum of the bottle is 0, and the initial momentum of the ball is (0.5)*(21)

we know that the final momentum of the bottle is (0.2)*(30) and the mass of the ball stays the same.

so that means that (0.5)*(21) = (0.2)*(30) + (0.5) * (final speed of ball)
 
so does that mean the answer would be 9?
(0.5)(21)=(0.2)(30)+(0.5)(x)
10.5=6+(0-5)(x)
x=9??
 
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