piper210_355
- 4
- 0
Physics prob 2 ... Help needed!
Like i sayed in my other posts this is probably easy but my teacher doesn't teach us anything so i don't have a clue how to do this. Can someone please explain how to do it?
A window washer pushes a sponge up a vertical window at a constant speed by applying a force. The sponge has a mass of .800 kg, and the coefficient of kinetic friction between the sponge and window is u_k=0.253. Determine the magnitude of the applied force, and the magnitude of the normal force exerted by the window on the sponge.
*There is a 20 degree angle( i put the pic below)
F(y) = weight of sponge + Frictional force
F(f) = u*F(x)
ok so what i did was that i took the sin 70 which if I'm not mistaken should equal F(x).
sin 70=F(x)
.94=F(x)
Then I put this in the equation for frictional force.
F(f)=uF(x)
F(f)=(.253)(.94)
F(f)=.238
After that I put it into the equation for F(y).
F(y)=weight of sponge + F(f)
F(y)=(.8)+(.238)
F(y)=1.048
My plan is to do the pythagorian therum to find the applied force, but I want to make sure i am doing it right so far.
Homework Statement
Like i sayed in my other posts this is probably easy but my teacher doesn't teach us anything so i don't have a clue how to do this. Can someone please explain how to do it?
A window washer pushes a sponge up a vertical window at a constant speed by applying a force. The sponge has a mass of .800 kg, and the coefficient of kinetic friction between the sponge and window is u_k=0.253. Determine the magnitude of the applied force, and the magnitude of the normal force exerted by the window on the sponge.
*There is a 20 degree angle( i put the pic below)
Homework Equations
F(y) = weight of sponge + Frictional force
F(f) = u*F(x)
The Attempt at a Solution
ok so what i did was that i took the sin 70 which if I'm not mistaken should equal F(x).
sin 70=F(x)
.94=F(x)
Then I put this in the equation for frictional force.
F(f)=uF(x)
F(f)=(.253)(.94)
F(f)=.238
After that I put it into the equation for F(y).
F(y)=weight of sponge + F(f)
F(y)=(.8)+(.238)
F(y)=1.048
My plan is to do the pythagorian therum to find the applied force, but I want to make sure i am doing it right so far.