- #1
bilalsyed25
- 1
- 0
The Question:
A boat is floating at rest in dense fog near a large cliff. The captain sounds a horn at water level and the sound travels through the salt water (1470 m/s) and the air (340 m/s) simultaneously. The echo in the water takes 0.40s to return. How much additional time will it take the echo in the air to return?
Relevent equations: v=d/t
My answer:
d = v∆t
d = 1470*0.40
d = 588/2 (I checked online for this question, some ppl got different answers due to this part; 558/2 or just 588?)
d = 294m
294/340 = 0.86s
0.86-0.40 = 0.46
Additional time = 0.46s
A boat is floating at rest in dense fog near a large cliff. The captain sounds a horn at water level and the sound travels through the salt water (1470 m/s) and the air (340 m/s) simultaneously. The echo in the water takes 0.40s to return. How much additional time will it take the echo in the air to return?
Relevent equations: v=d/t
My answer:
d = v∆t
d = 1470*0.40
d = 588/2 (I checked online for this question, some ppl got different answers due to this part; 558/2 or just 588?)
d = 294m
294/340 = 0.86s
0.86-0.40 = 0.46
Additional time = 0.46s