Physics problem: (speed of a point on earth)

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The speed of a point on the equator due to Earth's rotation is calculated using the formula v = (2*pi*r) / period, where the period is 24 hours. For a point at 45 degrees N latitude, the radius must be adjusted using trigonometry to find the effective radius. A right triangle can be drawn to visualize this, with the hypotenuse as Earth's radius and one side representing the radius at that latitude. The radial acceleration equation a = (V^2) / r is not directly applicable for calculating speed in this context. Understanding the correct radius is crucial for accurate calculations.
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What is the speed of a point on the equator of the Earth due to Earth's daily rotation?

What is the speed of a point at latitude of 45 degrees N?

Can I use the radial acceleration equation:
a = (V^2) / r

or

v = (2*pi*r) / period
where period = 24 hours = 86400s
 
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Well... since the problem asks for speed, don't you think you should use the formula for speed? :smile: (Be sure to use the correct radius.)
 
How do I figure out the radius at 45 degress latitude?
 
Draw yourself a picture. You'll find a right triangle whose hypotenuse is the radius of the earth. One of the sides is the radius you want. Use some trig.
 

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