Piecewise does not translate properly

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The discussion centers on a piecewise-defined function describing the distance traveled by a car before it stops, factoring in a driver reaction time and braking distance. The equations used yield conflicting results regarding the car's initial velocity, with one suggesting 18 m/s and the other 22.5 m/s, leading to confusion about the calculations. The total distance traveled before stopping is calculated as 53.3125 meters, but graphing the piecewise function shows an endpoint of (3.75, 40.5), raising questions about accuracy. Participants express concern over the inconsistencies in the problem's parameters and the implications for the piecewise function's translation. Overall, the thread highlights the complexities and potential errors in interpreting piecewise functions in physics problems.
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1. Homework Statement [/b]A car is driving at a constant velocity of 18 m/s. There is a school bus on the road with its stop sign extended. The car is 40 metres away from the bus when the driver sees the stop sign.
There is a time delay of 0.75 secondsbetween the time the driver sees the sign and when the driver can begin to slow down. This is called the "driver reaction time". During this reaction time the distance d, in m, traveled by the car is given by the equation d=18t, where t is the time in seconds from when the driver sees the bus. When brakes are applied, after the 0.75 second reaction time, the distance d traveled by the car in time t is given by the equation d=-3t^2+22.5t-1.6875. After the brakes are applied it takes 3 seconds for the car to come to a stop. These 3 seconds plus the 0.75 second driver reaction time means the car stops 3.75 seconds after seeing the school bus.
i) Write a piecewise-defined function to describe the distance traveled by the car until it stops.iv)how far does the car travel befor it stops?Explain how you found this.

d=(18t, 0<=t<=0.75
(-3t^2+22.5t-1.6875, 0.75<t<=3.75

When I solve the equations individually and add them together, I get 13.5+38.8125=53.3125
When I graph the piecewise on graphing calculator, I get a graph with an end coordinate of
(3.75, 40.5). How is this possible and which one is correct?
 
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I don't know anything about the graphing solution, but there is something odd about this problem. The formula d=18t says that the initial speed is 18 m/s. But the second term of d=-3t^2+22.5t-1.6875 says that the initial velocity is 22.5 m/s, a contradiction. The -1.6875 doesn't make any sense. If you use the acceleration of -3 from an initial speed of 22.5, you get a deceleration time of 7.5 s, not 3 s. The question has conflicts in it so it is not surprising that different methods result in different answers.
 
perhaps if i translate the parabola up 13.5 units and right 0.75 units we can get a better result. Something is lost in the translation from 2 individual functions to a piecewise. Any ideas are welcome and appreciated.
 
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