Pivoting Cylinder Homework: Find Angular Acceleration

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The discussion revolves around calculating the angular acceleration of a solid cylinder pivoting on a frictionless bearing, with a mass hanging from a string wrapped around it. The user attempted to derive the angular acceleration using the equation for torque, resulting in the expression (2mR)/(MR^2 - 2mR^2), but reported consistent errors in their calculations. Other participants encouraged the user to share their work for further analysis and troubleshooting. The focus is on identifying the mistake in the algebraic solution to correctly find the angular acceleration. Clarifying the steps taken in the calculation is essential for resolving the issue.
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Homework Statement

M, a solid cylinder (M=1.63 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder with a mass m = 0.830 kg is hung from the string, find the angular acceleration of the cylinder.

http://lc2.mines.edu/res/msu/physicslib/msuphysicslib/20_Rot2_E_Trq_Accel/graphics/prob16b_002masspulley2.gif

Homework Equations



torque = I(alpaha)

The Attempt at a Solution



I tried to solve the problem algebraically, and got (2mR)/(MR^2 - 2mR^2) but I keep getting it wrong.
 
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gonzalo12345 said:
I tried to solve the problem algebraically, and got (2mR)/(MR^2 - 2mR^2) but I keep getting it wrong.

Show us what you tried, and then we'll be able to see where the mistake was. :smile:
 
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