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Plane through origin perpendicular to another plane?

  1. Dec 6, 2012 #1
    1. The problem statement, all variables and given/known data
    Find a plane through the origin that meets the plane M : 2x + 3y + z = 12 in a right angle. How do you know your plane is perpendicular to M?


    2. Relevant equations
    Honestly have no idea... I know how to find an equation for a plane given a normal and a point, however.


    3. The attempt at a solution

    All I really know is that the normal of M, which is the perpendicular vector, would be <2,3,1>?
     
  2. jcsd
  3. Dec 6, 2012 #2

    Dick

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    Call your plane N. Then you want the normal of N to be perpendicular to the normal of M. There's a lot of choices that work. Pick one. Now it also has to pass through the origin. Now since you how to find an equation for a plane given a normal and a point, you should be done.
     
  4. Dec 6, 2012 #3
    How do you find a perpendicular plane though?
     
  5. Dec 6, 2012 #4

    Dick

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    Two planes are perpendicular if their normals are perpendicular. Find a vector that is perpendicular to <2,3,1>. Any one. There are lots of them. Use that as your normal for the new plane.
     
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