Planet orbiting around a star whose mass changes

AI Thread Summary
The discussion centers on a hypothetical scenario where a star loses half its mass and its effect on a planet's orbit. Participants express concerns about the assumption of a circular orbit after the mass change, noting that this scenario defies physical laws like conservation of momentum. The calculations presented suggest that if angular momentum is conserved, the new radius of the planet's orbit would be twice the original radius. However, there is skepticism about the validity of the problem due to the unrealistic nature of mass loss and its implications for momentum conservation. Ultimately, the conversation highlights the complexities and potential contradictions in the problem's assumptions.
FruitNinja
Messages
20
Reaction score
0

Homework Statement


(Assuming all circular orbits)
[/B]
Say there is a star with mass M and a planet orbiting that star with a mass m.

The star M then suddenly loses half of its mass. (So now it is M/2)

What is the new radius of orbit of the planet around the star? Warning: Velocity will not be the same!

I'm not sure how to tackle this problem. I know for sure it has to do with angular momentum

Homework Equations


[/B]
L=Iω or r x p angular momentum

The Attempt at a Solution


conservation of momentum for the planet
from Iωi = Iωf, I got m ri vi = m rf vf , but that doesn't really help
 
Physics news on Phys.org
FruitNinja said:
conservation of momentum for the planet
from Iωi = Iωf, I got m ri vi = m rf vf , but that doesn't really help
It helps, but you need another equation. What else will be conserved?
(But I have a concern about the question. It seems to assume the new orbit will be circular. That strikes me as most unlikely.)
 
haruspex said:
It helps, but you need another equation. What else will be conserved?
(But I have a concern about the question. It seems to assume the new orbit will be circular. That strikes me as most unlikely.)

yes, I know it is really not circular but It will be assumed in this probem.

I used f=ma to come up with vi=sqrt(GM/ri) & vf=sqrt(GM/2rf)and plugged in those as V on both sides (with the corresponding r)

I got 2 ri = rf
 
FruitNinja said:
yes, I know it is really not circular but It will be assumed in this probem.

I used f=ma to come up with vi=sqrt(GM/ri) & vf=sqrt(GM/2rf)and plugged in those as V on both sides (with the corresponding r)

I got 2 ri = rf
Looks ok. The trouble with questions with premisses that defy physical laws is that there may well be different solutions methods, all valid, that produce different answers.

Edit: and gneill has put his finger on just such an alternate answer. As I asked in post #2, what else should be conserved?
 
Last edited:
I have a feeling that this is a bit of a trick question, and not just because it invokes magic to make mass vanish. Assuming that the planet retains its current orbital speed at the instant half of the star's mass is vanished, I'd look at comparing that speed with the new escape velocity for that location.
 
  • Like
Likes PeroK
As I read the problem and guess at the author's thoughts, we are to assume that at the same moment half of the star magically vanishes, the planet does not change mass, but magically teleports to a new position with a new velocity, which are both chosen so that angular momentum is conserved and a circular orbit results.

It is strange that one would pose a problem in which angular momentum conservation is paramount using a scenario involving teleportation. Teleportation defies conservation of angular momentum.

Of course, neither linear nor angular momentum are conserved in this problem anyway. The star changes mass. That defies conservation of both quantities in a great number of frames of reference.
 
jbriggs444 said:
As I read the problem and guess at the author's thoughts, we are to assume that at the same moment half of the star magically vanishes, the planet does not change mass, but magically teleports to a new position with a new velocity, which are both chosen so that angular momentum is conserved and a circular orbit results.
 
jbriggs444 said:
... teleports to a new position with a new velocity, which are both chosen so that angular momentum is conserved and a circular orbit results.
As gneill and I have hinted, the author probably did not mean to imply assumption of a new circular orbit; rather, that something else is conserved.
Those two alternate assumptions lead to different answers.
 
  • Like
Likes jbriggs444
Back
Top