Exploring Planck Units: Why Newton's Constant?

In summary, the gravitational constant is a fundamental physical constant which appears in Newton's law of universal gravitation and in Einstein's theory of general relativity. It is a low gravity approximation and general relativity is what it used to work things out.
  • #1
PhiJ
44
0
I have been reading http://en.wikipedia.org/wiki/Planck_units
Why do they use Newton's universal gravitational constant, when that is a low gravity approximation and general relativity is what it used to work things out?
 
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  • #2
PhiJ said:
I have been reading http://en.wikipedia.org/wiki/Planck_units
Why do they use Newton's universal gravitational constant, when that is a low gravity approximation and general relativity is what it used to work things out?
Read http://en.wikipedia.org/wiki/Gravitational_constant , which is a link on that page.
It says "The gravitational constant is a fundamental physical constant which appears in Newton's law of universal gravitation and in Einstein's theory of general relativity."

This constant appears in the Einstein Field Equations (scroll down about 25% on your Planck_units reference).
 
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  • #3
OK, thanks, I should read more thoroughly next time.
 
  • #4
Wait a sec (or maybe a plank time :P), if the speed of light is a dimensionless constant, then shouldn't it be -i, as according to SR, time is distance*i, and speed = distance/time = x/ix = 1/i = -i.
Unless, of course I misunderstood my SR text, (v. likely) or GR changes it.
 
  • #5
The speed of light is not dimensionless... It's a speed... with SI units of m/s.
 
  • #6
You can also arrive at a different set of so called fundamental units of time, space and mass by combining G and c with the electron charge rather than h. All of which leads one to wonder if this process is little more than cosmic numerology with no real physical significance
 
  • #7
But time is a dimension, and so is distance. I got the impression from the SR sheet I was reading, that time*i*c=a spatial dimetsion. I assumed that the reason why you were mutiplying by c was not to multiply by metres and divide by time to get distance, but because we measure distance and time using a different 'stick', we use a shorter stick for distance than time, and we must convert. If we used the same stick, then t*i=x, and thus the speed of light is t*i/t=i (oops, I put -i earlier).

Somebody tell me I'm being stupid...
 
  • #8
You're not. Misinterpreted the old-fashioned [itex] ict=x^{0}=x_{0} [/itex] prescript for making the flat Minkowski metric [itex] \eta_{\mu\nu}\rightarrow \delta_{\mu\nu} [/itex].

In today's physics, we only encounter such anomalies when we do a Wick rotation, but that's another story...

Daniel.
 
  • #9
So the speed of light is i?
I was reading http://en.wikipedia.org/wiki/Wick_rotated. Why do you model all space times with squared dimensions. I see why in Minkowski, but not in Euclidian.
Also, what's the s on this page (in the formula with ds)

Thanks
 
  • #10
yogi said:
You can also arrive at a different set of so called fundamental units of time, space and mass by combining G and c with the electron charge rather than h. All of which leads one to wonder if this process is little more than cosmic numerology with no real physical significance
i think those are called "Stoney units" and had been defined before Planck. i think they had to also include the electron mass. you need 4 independent quantities to base 4 unit definitions on (length, time, mass, and charge). perhaps, now that i think of it, Stoney units normalize [itex] G [/itex], [itex] c [/itex], [itex] e [/itex], and [itex] 4 \pi \epsilon_0 [/itex] and the electron mass is not in the mix.

my feeling is that Planck units (or a small adjusment to them, i think that normalizing [itex] 4 \pi G [/itex] and [itex] \epsilon_0 [/itex] makes more natural sense than normalizing [itex] G [/itex] and [itex] 4 \pi \epsilon_0 [/itex] as is done in Planck units) is more natural than any system that is based on properties of any object or particle or "thing". Planck units are defined based on the properties of the vacuum of space and not of any "thing" in that space. i don't think it's an accident of Nature that there are 3 fundamental dimensions of quantity (length, mass, time) of which 3 fundamental base units had been defined completely anthropocentrically (meter, kilogram, second) which are used to measure three fundamental dimensionful constants ([itex] G [/itex], [itex] c [/itex], [itex] \hbar [/itex]) that are not properties of any "thing" in the universe only of the space of the universe itself.

then, given a natural unit of charge, you can ask what is the Fundamental charge in terms of that natural unit and the answer is the square root of the Fine-structure constant. and that actually makes a lot of sense since, in a physical system shorn of all dependence on anthropocentric units, [itex] \alpha [/itex] is the strength of the E&M interaction of fundamental particles. double the charge of the electron, proton, positron (or the quarks that make up these particles) and you quadruple their relative EM force on each other. and likewise quadruple [itex] \alpha [/itex].
 
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1. What are Planck units?

Planck units are a set of units used in theoretical physics that are based on fundamental physical constants, such as the speed of light, the gravitational constant, and the Planck constant. These units are often used in attempts to unify different theories of physics, such as general relativity and quantum mechanics.

2. Why is Newton's constant important in relation to Planck units?

Newton's constant, also known as the gravitational constant, plays a crucial role in Planck units because it is one of the fundamental constants used to define these units. It is used to describe the strength of the gravitational force between two objects and is a key factor in understanding the behavior of gravity at the smallest scales.

3. How are Planck units useful in theoretical physics?

Planck units are useful in theoretical physics because they provide a way to express physical quantities in a way that is independent of any particular system of units. This makes it easier to compare and combine different theories and models in physics, as well as to understand the fundamental forces and properties of the universe.

4. Are Planck units considered to be the smallest units of measurement?

While Planck units are often referred to as the "smallest" units of measurement, it is important to note that they are not necessarily the smallest physically possible units. They are simply the smallest units that can be defined using our current understanding of physics and the known fundamental constants.

5. How do Planck units relate to other systems of measurement?

Planck units are not commonly used in everyday measurement, as they are extremely small and often impractical to use. They are mainly used in theoretical physics and are often compared to other systems of measurement, such as the SI system or the imperial system, in order to gain a better understanding of the physical world.

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