A hockey puck B rests on smooth ice surface and is struck by a second puck A, which was originally traveling at 40.0 m/s and which is deflected 30.0° from its original direction. Puck B acquires a velocity at a 45.0° angle to the original direction of A. The pucks have the same mass. Compute the speed of each puck after the collision.(adsbygoogle = window.adsbygoogle || []).push({});

Va2 =speed puck A after collision

Vb2 = speed puck B after collision

So far my work is:

Since the momentum is conserved for both components I did this.

Va2 = (40-Vb2*(cos(45) )/cos(30)

Vb2 = (-Va2*sin(30) )/sin(45)

Okey. I have 2 unknowns I need to find and 2 equations.

When I compute these 2 I don't get the right answer.

The right answer is Va2=29.3 and Vb2=20.7

Could someone please give me a hint to what I'm doing wrong.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Playing hockey

**Physics Forums | Science Articles, Homework Help, Discussion**