A hockey puck B rests on smooth ice surface and is struck by a second puck A, which was originally traveling at 40.0 m/s and which is deflected 30.0° from its original direction. Puck B acquires a velocity at a 45.0° angle to the original direction of A. The pucks have the same mass. Compute the speed of each puck after the collision. Va2 =speed puck A after collision Vb2 = speed puck B after collision So far my work is: Since the momentum is conserved for both components I did this. Va2 = (40-Vb2*(cos(45) )/cos(30) Vb2 = (-Va2*sin(30) )/sin(45) Okey. I have 2 unknowns I need to find and 2 equations. When I compute these 2 I don't get the right answer. The right answer is Va2=29.3 and Vb2=20.7 Could someone please give me a hint to what I'm doing wrong.