PLEASE Can any one solve this problem

  • Thread starter spsundaram
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In summary, the distance an object falls under gravity in a time t, in the absence of air resistance, can be calculated using the formula d = 1/2 * g * t^2. When comparing the distances 2D and D, where 2D is the total distance traveled and D is the distance traveled in one second, we can substitute D into the formula to solve for T, the total time of the fall. This calculation does not require knowing the actual height of the tower or the value of g.
  • #1
spsundaram
1
0
A body dropped from a tower travels half of the total distance in the last second of its motion
.The total time taken of will be ...?
take g = 10 m/s^2

choices

a) square root 2 secs

b) 2 secs

c) 2+square root 2 secs

d) 2*square root 2 secs
 
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  • #2
Do you know your basic kinematics formulas?
 
  • #3
You will need to write down the formula for the distance an object falls under gravity in a time t, in the absence of air resistance. You then need to make a comparison between

the distance 2D that the object falls in T seconds

and

the distance D that the object falls in 1 second .

You do not need to know the actual height of the tower, which we've called 2D, since you will be substituted for D using your second equation. This will give you enough information to solve for T, the total time of the fall. (You'll also find that we don't actually care what value g has...)
 

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