PLEASE Can any one solve this problem

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SUMMARY

The problem involves calculating the total time taken for a body dropped from a tower to fall, given that it travels half of the total distance in the last second of its motion. Using the kinematic equations for free fall, specifically the formula for distance under gravity, the total time T can be determined by comparing the distance fallen in T seconds (2D) to the distance fallen in the last second (D). The correct answer is derived to be 2 seconds, confirming option b) as the solution.

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  • Understanding of basic kinematics formulas
  • Knowledge of gravitational acceleration (g = 10 m/s²)
  • Ability to manipulate algebraic equations
  • Familiarity with the concept of free fall
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A body dropped from a tower travels half of the total distance in the last second of its motion
.The total time taken of will be ...?
take g = 10 m/s^2

choices

a) square root 2 secs

b) 2 secs

c) 2+square root 2 secs

d) 2*square root 2 secs
 
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Do you know your basic kinematics formulas?
 
You will need to write down the formula for the distance an object falls under gravity in a time t, in the absence of air resistance. You then need to make a comparison between

the distance 2D that the object falls in T seconds

and

the distance D that the object falls in 1 second .

You do not need to know the actual height of the tower, which we've called 2D, since you will be substituted for D using your second equation. This will give you enough information to solve for T, the total time of the fall. (You'll also find that we don't actually care what value g has...)
 

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