Please check my Answer to Free Fall Question

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The discussion revolves around a physics problem involving the vertical throw of keys, with a focus on calculating initial and final velocities. The initial speed of the keys was calculated to be approximately 10.016 m/s, while the final speed before being caught is around 4.68333 m/s. A key point raised is the distinction between speed and velocity, emphasizing that the latter includes direction, which is not captured by simply taking the square root of the final velocity equation. Participants suggest using a different kinematic equation to clarify the direction of the final velocity. The conversation highlights the importance of understanding the signs associated with velocity in physics problems.
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Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.

Homework Equations


The Attempt at a Solution



d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR 7-A ->>Vi= 10.016 m/s

Vf^2 = Vi^2 +2ad

Vf= √(10.016m/s)2+2ad

Vf= 4.68333 m/s
 
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Hi cbrowne,

cbrowne said:

Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.

Homework Equations





The Attempt at a Solution



d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR 7-A ->>Vi= 10.016 m/s

Vf^2 = Vi^2 +2ad

Vf= √(10.016m/s)2+2ad

Vf= 4.68333 m/s

I don't believe that equation will answer the question. It gives the speed, but they are asking for the velocity.

When you use the equation:

Vf^2 = Vi^2 +2ad

you have to remember that because the Vf and Vi are squared, the equation does not differentiate between positive and negative velocities. So all that equation is telling you is that after taking the square root:

<br /> V_f = \pm 4.68333 \mbox{ m/s}<br />

(For example, what is the square root of 4? It is both +2 and -2.) So you still have to determine which sign is the correct sign. Try using another kinematic equation that has the final velocity in it to determine the direction. What do you get?
 
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