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**1. Homework Statement**

What is the height of a geostationary satellite measured from the earth's centre?

**2. Homework Equations**

r^3/T^2 = GM/4pi^2

T of earth = 3.16 * 10^7 s

**3. The Attempt at a Solution**

GM/4p2 = r3/T2

3root[T2 * GM/4p2 ] = r

3root[(3.16*107 s)2 * ((6.67*10^ -11N * m2 /kg2 )(5.98*1024 kg)/4p2 )] = r

2.16*109m = r

Therefore the height of the satellite from the Earth’s center is 2.16*109m.