Please help : Homework problem almost there ? Equilibrium

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The discussion revolves around calculating the concentrations of species at equilibrium for the reaction H2O + Cl2O --> 2HOCl under two scenarios. In the first scenario, 1.00g of water and 4.78g of ClO are mixed in a 1.0L flask, while in the second, 1.0 mol of pure HOCl is placed in a 2.0L flask. The equilibrium constant Kc is given as 0.090, and the participants emphasize the importance of using concentrations in the equilibrium expression. There is a suggestion to verify the correct reaction equation and consider the nature of the reaction as an acid-base interaction. Accurate calculations of x will lead to the determination of all species at equilibrium.
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Kc = .090

a). Calculate the concn. of all species at equilibrium if 1.00g of water and 4.78g of ClO are mixed in a 1.0L flask.

b). Calculate the concn. of all species at equilibrium if 1.0 mol of pure HOCl is placed in a 2.0L flask. Hint: consider what is now the reactant.





H2O + Cl2O --> 2HOCl

I| 18mol 88 mol 0
C| -x -x +x
E| 18-x 88-x x

Kc= .090 = [HOCl]2 / [H2O].[Cl2O] = x2/(18-x)(88-x)


Solve for x and find all species.Is this the correct way ? Am I confusing you... *hmmm*
 
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You're getting there, but you could use a little hint --- the equilibrium constant is written for CONCENTRATIONS --- you've got the stoichiometry in the exponents correctly --- what are the "concentrations?"
 
You said that the reaction involved clo- and water which would be an acid base reaction.

Check to see if you wrote down the correct equation.

Acid base reaction would make more sense.
 
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