- #1

stonecoldgen

- 109

- 0

^{3}θ and that y=sin

^{3}θ

if (d

^{2}y/dx

^{2})=[(dy/dθ)/(dx/dθ)]/[dx/dθ] is right, wouldn´t the second derivative of the parametric be:

1/3c

^{3}θ ??

I got this by using dy/dθ=3sin

^{2}θ,

and dx/dθ=-3cos

^{2}θsinθ

any idea what's wrong? or is it right?