Proving y=ln|x| and its Limits: A Comprehensive Guide

  • Thread starter Ayinajin
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In summary, the conversation discusses two mathematical proofs involving the natural logarithm function. The first proof shows that the derivative of ln|x| is equal to 1/x. The second proof involves the limit of ln|x| as x approaches positive infinity and 0 from the positive side, which is shown to be positive and negative infinity respectively.
  • #1
Ayinajin
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I’ll appreciated very much if anyone can help me with any of these following proves by any means. Thank you!

prove:
1. y=ln|x| = y'=1/x

2. lim ln|x|=+ infinity as x approaches toward positive infinity and-
lim ln|x| = - infinity as x approaches 0 from positive side
 
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  • #2
Maybe something like this... Let f(x) = exp(ln(x)), where exp(x) = e^x. Using the chain rule, we have that f'(x) = exp(ln(x)) * d/dx(ln(x)) = x * d/dx(ln(x)). But since f(x) = x, we must also have f'(x) = 1. Thus x * d/dx(ln(x)) = 1, or d/dx(ln(x)) = 1/x.
 
  • #3
Muzza said:
Maybe something like this... Let f(x) = exp(ln(x)), where exp(x) = e^x. Using the chain rule, we have that f'(x) = exp(ln(x)) * d/dx(ln(x)) = x * d/dx(ln(x)). But since f(x) = x, we must also have f'(x) = 1. Thus x * d/dx(ln(x)) = 1, or d/dx(ln(x)) = 1/x.

Thank you Muzza! That was beautiful! How about my second problem?
 

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