How Can I Increase Current from a CD4017 IC to Fire a Relay?

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SUMMARY

The discussion focuses on increasing current output from a CD4017 IC to successfully fire a relay. Users recommend using a 2N3904 transistor to switch loads up to 100 mA, as the CD4017 cannot provide sufficient current directly. A flyback diode, such as the 1N4001, is essential to protect the transistor from voltage spikes when the relay is deactivated. Participants emphasize the importance of selecting a transistor rated for the desired load and checking relay datasheets for integrated diodes.

PREREQUISITES
  • Understanding of CD4017 IC functionality
  • Knowledge of transistor operation, specifically the 2N3904
  • Familiarity with relay circuits and their components
  • Basic electronics knowledge, including the concept of flyback diodes
NEXT STEPS
  • Research the specifications and applications of the 2N3904 transistor
  • Learn about relay selection criteria and load ratings
  • Study the role of flyback diodes in inductive load circuits
  • Explore alternative transistors for higher current applications
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Electronics enthusiasts, hobbyists building relay circuits, and engineers seeking to control high-current loads using low-power ICs.

Sightsound
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Hi guys I'm new here and need map some help. I have built a simple circuit with a cd4017 IC. The circuit works perfectly and has led connected to it. However I want to connect much larger load to it. A relay is the obvious answer but I'm not getting enough current from the IC to fire the relay. I tried using a triac but the triac latches and I'm led to believe that this is because it's a dc load, the relay. I'm stuck now any suggestions welcome please.
 
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a transistor would be a better/easier way to go unless you were switching more that say 10A

attachment.php?attachmentid=72084&stc=1&d=1407801780.gif


OK I have drawn this one ... still switching a LED
The 2N3904 transistor will switch a couple of 100 mA

choose a transistor rated for a current and load you want to switch

for high currents, you could replace the LED and 1k resistor with a relay ... don't forget to add a reverse biased diode (1N4001) across the relay coil, else you will kill the transistor

Dave
 

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More often than not you will find that you have to turn things on in stages because the control IC doesn't provide enough current to drive the switching device. Davenn's suggestion is good. I just wanted to add that the reverse biased diode he mentioned is often called a "flyback diode" and it is sometimes included inside the relay itself. Check your datasheet for your relay to see if it has a diode.
 

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