How to Calculate Moles of H2O and Kp in a Decomposition Reaction?

  • Thread starter Thread starter gdsmack267
  • Start date Start date
  • Tags Tags
    Equilibrium
AI Thread Summary
To calculate the moles of H2O in the decomposition reaction of NaHCO3, start with the balanced equation: 2NaHCO3(s) <--> Na2CO3(s) + H2O(g) + CO2(g). Given 100 grams of NaHCO3 in a 5 L container at 160 degrees C with a total pressure of 7.76 atm, use the ideal gas law (PV=nRT) to find the moles of water produced at equilibrium. Understanding stoichiometry and balancing chemical equations is crucial for solving these problems effectively. The equilibrium constant Kp can be calculated using the partial pressures of the gases involved. Mastering these foundational concepts will enable successful problem-solving in chemical equilibrium.
gdsmack267
Messages
2
Reaction score
0
I have been trying to this problem for an hour now and i have no clue what to do and where to start.

Given equation- 2NaHCO3(s)<-->Na2CO3(s)+H2O(g)+CO2(g)
a. A sample of 100 grams of solid NaHCO3 was placed in an 5 L container and heated to 160 degrees C. Some of the original solid remained and the total pressure in the container was 7.76 atmospheres when equilibrium was reached. Calculate the number of moles of H2O present at equilibrium. (NaHCO3 molar mass= 84 g, PV=nRT, R=.08206 L atm/mol K)
b. How many grams of the original solid remain in the container under the conditions described in "a"?
c.Write the equilibrium expression for the equilibrium constant Kp and calculate its value for the reaction under the conditions in "a".
d. If 115 g. of solid NaHCO3 had been placed in the 5 L container and heated to 160 degrees C, what would have the total pressure been at equilibrium?
 
Chemistry news on Phys.org
Where to start : write and balance the equation for the decomposition of sodium bicarbonate.
 
how do you do that?
 
You need to figure that out way before you start solving problems in chemical equilibrium. In this case, that part has already been done for you.

You need to get your basics first. There's no way you can solve these problems without knowing how to balance chemical equations. A suggestion : read your text.
 
2NaHCO3(s)<-->Na2CO3(s)+H2O(g)+CO2(g)

First of all when an equation is given to you, check to see whether it's balance. Equations hold key information like stoichiometric proportions in a reaction.

e.g. check to see whether 2 atoms of Na on the left corresponds to 2 atoms of Na on the right, and so on for the rest of the elements.

From the ideal gas equation PV = nRT with some information given to you like pressure, temperature etc. What is the unknown in the equation? Don't forget that you R constant is in L.atm/mol.k

Hope this helps you to start. :smile:
 
Thread 'How to make Sodium Chlorate by Electrolysis of salt water?'
I have a power supply for electrolysis of salt water brine, variable 3v to 6v up to 30 amps. Cathode is stainless steel, anode is carbon rods. Carbon rod surface area 42" sq. the Stainless steel cathode should be 21" sq. Salt is pure 100% salt dissolved into distilled water. I have been making saturated salt wrong. Today I learn saturated salt is, dissolve pure salt into 150°f water cool to 100°f pour into the 2 gallon brine tank. I find conflicting information about brine tank...
Engineers slash iridium use in electrolyzer catalyst by 80%, boosting path to affordable green hydrogen https://news.rice.edu/news/2025/engineers-slash-iridium-use-electrolyzer-catalyst-80-boosting-path-affordable-green Ruthenium is also fairly expensive (a year ago it was about $490/ troy oz, but has nearly doubled in price over the past year, now about $910/ troy oz). I tracks prices of Pt, Pd, Ru, Ir and Ru. Of the 5 metals, rhodium (Rh) is the most expensive. A year ago, Rh and Ir...
Back
Top