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Please solve this one

  1. Sep 21, 2007 #1
    Y=4 x=2
    ∫ ∫ Sinx ∕ x^2 dx dy
    Y=0 x=√y
  2. jcsd
  3. Sep 21, 2007 #2


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    Staff: Mentor

    Can one find an integral table with

    [tex] \int \frac{sin\,x}{x^2}\,dx [/tex] ?

    Alternatively, expand sin x as an infinite series, divide by x2 and solve for each term.
  4. Sep 22, 2007 #3
    i changed the order of the integration....the final answer i had is the same one in the sheet from which i get the problem......but i don't know id the way i solved it is right or wrong....please HELP...
    X=2 y=x^2
    ∫ ∫ sinx/x^2 dx dy
    X=0 y=0

    X=2 y=x^2
    = ∫ [(sinx/x^2)y] dx
    X=0 y=0

    =∫ sinx dx
    = [ -cosx]

    = -cos2+cos(0)= 1-cos2
  5. Sep 22, 2007 #4


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    Science Advisor
    Homework Helper

    That is correct.
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