Pneumatic Cylinder to open Hatch

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SUMMARY

The discussion focuses on designing a pneumatic system to open a 500lb hatch using a pneumatic cylinder and a bell crank mechanism. The hatch must open to 110 degrees within 10 seconds. Key calculations include determining the necessary acceleration using the equation of motion and calculating torque based on the inertia of the rotating object. From the torque, the required force can be derived using the formula F = T/r, where r is the radial distance from the pivot point.

PREREQUISITES
  • Pneumatic system design principles
  • Understanding of torque and force calculations
  • Basic knowledge of mechanical systems and bell crank mechanisms
  • Familiarity with equations of motion
NEXT STEPS
  • Calculate the acceleration required for the hatch using the equation of motion
  • Determine the torque needed based on the inertia of the hatch
  • Research pneumatic cylinder sizing based on force requirements
  • Explore diagrams and layouts for effective pneumatic system design
USEFUL FOR

Mechanical engineers, pneumatic system designers, and anyone involved in automating heavy hatch operations will benefit from this discussion.

jrobinson
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Hey everyone,

Having a little trouble with something a little out of my element. I've been tasked to design a pneumatic system to open a ~500lb hatch. I think I'm leaning towards a pneumatic cylinder to act on a bell crank. I need the hatch to open to 110 degrees from zero in about 10 seconds.

Where I'm getting stuck is on the force necessary to perform this action so I can size my cylinder and then the rest of the system. Any help would be greatly appreciated.
 
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What is the layout like? You need to describe how the hatch is constrained and what it looks like. Diagrams are really helpful in these cases.
 
jrobinson said:
Hey everyone,

Having a little trouble with something a little out of my element. I've been tasked to design a pneumatic system to open a ~500lb hatch. I think I'm leaning towards a pneumatic cylinder to act on a bell crank. I need the hatch to open to 110 degrees from zero in about 10 seconds.

Where I'm getting stuck is on the force necessary to perform this action so I can size my cylinder and then the rest of the system. Any help would be greatly appreciated.

1st of all calculate the acceleration

acceleration can calculated by using equation of motion,

aceeleration= 2ө/ (tXt)
where ө= total angle travelled, (in your case it is 110 degrees)
t= time taken for traveling the angle ө(in your case it is 10 sec.)

torque, T= (inertia of the rotating object) X acceleration


From th torque u can calculate the force required...

Force F=Tr, where r is the radial distance @ which u r rotating the object...
 

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