- #1

joshmccraney

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PolarPlot[1, {\[Theta], \[Pi]/2, -\[Pi]/2}]

? Shouldn't I get the left side?

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- #1

joshmccraney

Gold Member

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PolarPlot[1, {\[Theta], \[Pi]/2, -\[Pi]/2}]

? Shouldn't I get the left side?

- #2

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- #3

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Note that ##\theta=0## is in the range from ##\pi/2## to ##-\pi/2##, so you expect to get the side of the circle containing 0.

PolarPlot[1, {\[Theta], \[Pi]/2, -\[Pi]/2}]

? Shouldn't I get the left side?

What you want is the range from ##\pi/2## to ##3\pi/2## which does not contain 0.

- #4

joshmccraney

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this makes tons of sense, thanks!

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