Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Polarizability of Liquid Helium

  1. Mar 4, 2008 #1
    1. The problem statement, all variables and given/known data

    What's the polarizability of liquid helium given:

    density= 145kgm^-3
    relative permittivity = X = 1.0566

    2. Relevant equations

    alpha (polarizability) = (3(permittivity of free space))/N) / ((X-1)/(X+2))

    3. The attempt at a solution

    because N is molecules/volume, N=145/6.645x10^-27=2.18x10^28

    plug everything in I get alpha = 2.26x10^-41

    but I have no idea if this is right or not because i've never had to calculate it before??
    Last edited: Mar 4, 2008
  2. jcsd
  3. Mar 5, 2008 #2
    well that's great, thanks for all the help :/
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook