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mikehibbert
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Homework Statement
What's the polarizability of liquid helium given:
density= 145kgm^-3
relative permittivity = X = 1.0566
Homework Equations
alpha (polarizability) = (3(permittivity of free space))/N) / ((X-1)/(X+2))
The Attempt at a Solution
because N is molecules/volume, N=145/6.645x10^-27=2.18x10^28
plug everything in I get alpha = 2.26x10^-41
but I have no idea if this is right or not because I've never had to calculate it before??
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