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Polarizability of Liquid Helium

  1. Mar 4, 2008 #1
    1. The problem statement, all variables and given/known data

    What's the polarizability of liquid helium given:

    density= 145kgm^-3
    relative permittivity = X = 1.0566

    2. Relevant equations

    alpha (polarizability) = (3(permittivity of free space))/N) / ((X-1)/(X+2))

    3. The attempt at a solution

    because N is molecules/volume, N=145/6.645x10^-27=2.18x10^28

    plug everything in I get alpha = 2.26x10^-41

    but I have no idea if this is right or not because i've never had to calculate it before??
    Last edited: Mar 4, 2008
  2. jcsd
  3. Mar 5, 2008 #2
    well that's great, thanks for all the help :/
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