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## Homework Statement

What's the polarizability of liquid helium given:

density= 145kgm^-3

relative permittivity = X = 1.0566

## Homework Equations

alpha (polarizability) = (3(permittivity of free space))/N) / ((X-1)/(X+2))

## The Attempt at a Solution

because N is molecules/volume, N=145/6.645x10^-27=2.18x10^28

plug everything in I get alpha = 2.26x10^-41

but I have no idea if this is right or not because I've never had to calculate it before??

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