- #1
Pseudo Statistic
- 391
- 6
We just started these at school, but I have some questions..
Inequalities on number line (x) graphs..
Using x = 0 testpoint..
Let's say I have (x+2)(x-4) > 0, (0 + 2)(0 - 4) would be -8, and -8 !>0, so it would be a disjunction, right? But if it was positive and satisfied the inequality, it would be a conjunction, right?
OR what if it was < 0 instead, if it satisfied it would be a disjunction and if it didn't satisfy it would be a conjunction, right?
And let's say I have x(x-2)(x+4) > 0, the teacher taught us this method where we plot -4, 2 and 0 on a number line and place positive signs and negative signes over each one accordingly so that the satisfying inequality would be where the 3 signs ontop of each other would be + or -, according to the inequality...
IS there an easier way to do this?
I'm sorry that I don't make much sense, I'm in a hurry...
Hope someone can make sense of my words and help!
Thanks.
Inequalities on number line (x) graphs..
Using x = 0 testpoint..
Let's say I have (x+2)(x-4) > 0, (0 + 2)(0 - 4) would be -8, and -8 !>0, so it would be a disjunction, right? But if it was positive and satisfied the inequality, it would be a conjunction, right?
OR what if it was < 0 instead, if it satisfied it would be a disjunction and if it didn't satisfy it would be a conjunction, right?
And let's say I have x(x-2)(x+4) > 0, the teacher taught us this method where we plot -4, 2 and 0 on a number line and place positive signs and negative signes over each one accordingly so that the satisfying inequality would be where the 3 signs ontop of each other would be + or -, according to the inequality...
IS there an easier way to do this?
I'm sorry that I don't make much sense, I'm in a hurry...
Hope someone can make sense of my words and help!
Thanks.