Position of package when dropped from plane

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When a package is dropped from a plane flying horizontally at 148 m/s from a height of 4510 m, it will continue to move forward at the same horizontal speed while falling. The time taken for the package to hit the ground can be calculated using the formula for free fall, which is influenced by gravity at 9.8 m/s². The initial vertical velocity of the package is zero, as it is dropped. As a result, the plane will be ahead of the package when it reaches the ground due to its horizontal motion. Understanding the separation of horizontal and vertical motion is key to solving this problem.
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Homework Statement



A plane is flying horizontally with speed 148 m/s at a height 4510 m above the ground, when a package is dropped from the plane. The acceleration is 9.8 m/s^2. Neglecting air resistance, when the package hits the ground, the plane will be... ahead, directly above, or behind the package?

Homework Equations



v^2 = vi^2 + .5ax

The Attempt at a Solution



I tried to break it into x and y components, and solve for x in the horizontal direction, but I am really confused. Please help.
 
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What is the initial velocity of the package in the y-direction?
How much time the packet takes to reach the ground?
 

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