Post-Impact Speed of Colliding Billiard Balls

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In a perfectly elastic collision between two identical billiard balls, conservation of momentum and kinetic energy principles apply. The first ball is moving north at 15.0 m/s, while the second is moving south at 10.0 m/s. Since the balls are identical, their masses can be considered equal, simplifying calculations. The post-impact speeds can be determined using the equations derived from these conservation laws. The discussion emphasizes the need to apply these principles without requiring specific mass values due to the balls being identical.
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Homework Statement



Two billiard balls, one heading north at 15.0 m/s and a second heading south at 10.0 m/s, collide head-on. Take the collision to be perfectly elastic and choose the positive direction north.

What is the post-impact speed of the first ball
Answer: m/s

What is the post-impact speed of the second ball?
Answer: m/s


Homework Equations





The Attempt at a Solution



Don't even know where to start.
 
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You start by applying conservation of momentum and conservation of kinetic energy.
 
But don't i need the mass in order to do that?
 
They are identical billiard balls I assume, in mass and otherwise.
 

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