im trying to do this problem involving the postion of a rocket going straight up at a given time. it says a rocket initially at rest on the ground, accelerates straight upward from rest with constant net acceleration a, until time t(subscript 1) when the fuel is exhausted. the equation for this is: position at that time=initial position+initial velocity times t(time)+0.5 times 3 times 9.81m/s^2 times T^2 i know initial velocity and position are zero, so all i got left over is the rest of the equation. a=3g(g being accel. due to gravity) and T(subscript 1)=5.00s it says to give ur answer in meters. i ended up with 368 meters. but it said that i forgot a numerical factor?