Postion-time graph and velocity

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The slope of a position-time graph represents the velocity of an object, as it indicates the change in position over time. The units of the slope should correspond to the units of velocity, confirming its definition. Understanding this relationship is crucial for analyzing motion. The discussion emphasizes the importance of verifying the units to ensure consistency with velocity. This foundational concept is key in physics for interpreting motion graphs accurately.
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Is the slope on a postion-time graph, the velocity?
 
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That is correct. The slope of position vs. time graph gives the change in position of an object with respect to time, which is, by definition, the velocity of the object. Try to find the units of the slope of the graph. They should match with units of velocity.
 
G01 said:
That is correct. The slope of position vs. time graph gives the change in position of an object with respect to time, which is, by definition, the velocity of the object. Try to find the units of the slope of the graph. They should match with units of velocity.
Thanks :) Just wanted to make sure.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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