Potential energy of a system (gravity)

AI Thread Summary
The potential energy of a system with four equal particles, each of mass M at the corners of a square with side length d, is given by ep = - (G M^2 / d) * (4 + √(2)). To solve the problem, one must calculate the work required to move the particles to infinity, as the gravitational potential is zero at that point. This involves considering the work done to separate the particles one by one. The negative of this work will yield the potential energy of the system. Understanding this concept is crucial for grasping the relationship between gravitational force and potential energy.
jjr
Messages
51
Reaction score
1

Homework Statement


Show that the potential energy of a system which consists of four equal particles, each with mass M, that are placed in different corners of a square with sides of length d, is given by
ep = - \frac{G M^2}{d}*(4 + √(2))

Homework Equations



The gravitational force F(r) = - \frac{G M m}{r^2} * ur
Potential gravitational energy Ep(r) = - \frac{G M m}{r}


The Attempt at a Solution



I'm having a hard time achieveing an intuitive comprehension of how one might solve this problem. As far as I can understand, they're asking how much work would be done if all the particles moved into the center? I'm not sure if I should figure out the work it would take to bring each individual particle into the center one at a time, all at once, or if I need to approach this in some other way.. Any hints would be greatly appreciated

Thanks in advance,
J
 
Physics news on Phys.org
jjr said:
As far as I can understand, they're asking how much work would be done if all the particles moved into the center?

The gravitational potential is zero at infinity. You need to calculate the work needed to take the system apart, to move the particles one by one to infinity. The negative of that work is equal to the potential energy of the system.


ehild
 
Of course! Thanks:)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top