Potential Energy problem homework

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SUMMARY

The discussion centers on calculating the potential energy gain of a girl weighing 470N suspended from an 8-meter rope when swung to an angle of 35º with the vertical. The relevant equation used is PE = mgh, where the gravitational acceleration is noted as 9.7 m/sec². The calculations presented yield a potential energy change of 680 Joules, which does not match the desired answer of 679.5 Joules. Participants suggest using the cosine of the angle to simplify the calculation and express confusion regarding the professor's insistence on a free body diagram and the specific value of gravitational acceleration.

PREREQUISITES
  • Understanding of potential energy calculations using the formula PE = mgh
  • Familiarity with trigonometric functions, specifically cosine
  • Basic knowledge of free body diagrams in physics
  • Concept of gravitational acceleration and its application in potential energy problems
NEXT STEPS
  • Review the derivation and application of the potential energy formula PE = mgh
  • Learn how to construct and interpret free body diagrams in physics
  • Study the effects of gravitational acceleration variations on potential energy calculations
  • Explore the relationship between angle and height in pendulum motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and potential energy calculations, as well as educators seeking to clarify concepts related to free body diagrams and gravitational effects.

aspirare21
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Hello guys I need your help T__T I'm new here.. ^__^

Homework Statement


A girl weighing 470N hangs suspended on the end of a rope 8 meters long. What will be her gain in potential energy when a boy swings her to one side so that the rope makes an angle of 35º with the vertical? gravity= 9.7 m/sec²

I need the answer to be exactly 679.5 Joules.. My professor wants that I use an equation with Fg? (Free body diagram)? Or any solution that will leads to the exact answer..

Homework Equations



PE=mgh

The Attempt at a Solution


PE''=mgh mg (470N) x h (8 meters)
=3760

PE'=mgh 470 x (cos 35º) x 8
=3080

3760-3080=680
 
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Welcome to PF!

Hello aspirare21! Welcome to PF! :smile:
aspirare21 said:
A girl weighing 470N hangs suspended on the end of a rope 8 meters long. What will be her gain in potential energy when a boy swings her to one side so that the rope makes an angle of 35º with the vertical? gravity= 9.7 m/sec²

I need the answer to be exactly 679.5 Joules.. My professor wants that I use an equation with Fg? (Free body diagram)? Or any solution that will leads to the exact answer..

PE''=mgh mg (470N) x h (8 meters)
=3760

PE'=mgh 470 x (cos 35º) x 8
=3080

3760-3080=680

Well, I get exactly the same answer as you (not 679.5).

(btw, using 1- cos35º in the first place would have been quicker and neater :wink:)

Also, I don't understand what your professor thinks g has to do with it (nor why it's only 9.7 ! :rolleyes:) … the weight is given in Newtons.

(I assume the equation your professor is thinking of is PE = (minus) work done = force "dot" distance = Fg.x = Fgh :confused:)
 
Hello tiny-tim :)

I myself is confuse on how he derive the g=9.7 m/sec². He wants us to show a free body diagram on how to solve it.. Maybe putting tension,normal force,etc. I don't know if the formula or the pendulum is applicable here.. But this problem doesn't have a velocity. :(
 

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