Potential Energy problem homework

AI Thread Summary
A girl weighing 470N is suspended from an 8-meter rope, and the problem requires calculating her potential energy gain when swung to a 35º angle with the vertical. The initial calculations yield potential energy values of 3760 Joules and 3080 Joules, resulting in a difference of 680 Joules, which does not match the required 679.5 Joules. There is confusion regarding the use of gravity as 9.7 m/sec² and the necessity of a free body diagram, as the weight is already provided in Newtons. Participants suggest that using 1 - cos(35º) could simplify the calculations. The discussion highlights the need for clarity in the problem's requirements and the application of relevant physics concepts.
aspirare21
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Hello guys I need your help T__T I'm new here.. ^__^

Homework Statement


A girl weighing 470N hangs suspended on the end of a rope 8 meters long. What will be her gain in potential energy when a boy swings her to one side so that the rope makes an angle of 35º with the vertical? gravity= 9.7 m/sec²

I need the answer to be exactly 679.5 Joules.. My professor wants that I use an equation with Fg? (Free body diagram)? Or any solution that will leads to the exact answer..

Homework Equations



PE=mgh

The Attempt at a Solution


PE''=mgh mg (470N) x h (8 meters)
=3760

PE'=mgh 470 x (cos 35º) x 8
=3080

3760-3080=680
 
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Hello aspirare21! Welcome to PF! :smile:
aspirare21 said:
A girl weighing 470N hangs suspended on the end of a rope 8 meters long. What will be her gain in potential energy when a boy swings her to one side so that the rope makes an angle of 35º with the vertical? gravity= 9.7 m/sec²

I need the answer to be exactly 679.5 Joules.. My professor wants that I use an equation with Fg? (Free body diagram)? Or any solution that will leads to the exact answer..

PE''=mgh mg (470N) x h (8 meters)
=3760

PE'=mgh 470 x (cos 35º) x 8
=3080

3760-3080=680

Well, I get exactly the same answer as you (not 679.5).

(btw, using 1- cos35º in the first place would have been quicker and neater :wink:)

Also, I don't understand what your professor thinks g has to do with it (nor why it's only 9.7 ! :rolleyes:) … the weight is given in Newtons.

(I assume the equation your professor is thinking of is PE = (minus) work done = force "dot" distance = Fg.x = Fgh :confused:)
 
Hello tiny-tim :)

I myself is confuse on how he derive the g=9.7 m/sec². He wants us to show a free body diagram on how to solve it.. Maybe putting tension,normal force,etc. I don't know if the formula or the pendulum is applicable here.. But this problem doesn't have a velocity. :(
 
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