Potential of concentric cylindrical insulator & conducting shell. Stuck on 2nd question

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SUMMARY

The discussion focuses on calculating the electric field and potential difference in a system comprising an infinitely long solid insulating cylinder and a concentric conducting shell. The insulating cylinder has a charge density of ρ = 23 μC/m³ and a radius of a = 5.2 cm, while the conducting shell has an inner radius of b = 14.2 cm and an outer radius of c = 16.2 cm, with a linear charge density of λ = -0.45 μC/m. The electric field at point R, located 58 cm from the origin, is calculated to be Ey(R) = -7897.28 N/C. The potential difference between the outer surface of the conductor and the outer surface of the insulator is derived using the formula V(c) - V(a) = kq * (1/c - 1/a).

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This discussion is beneficial for physics students, electrical engineers, and anyone interested in electrostatics, particularly in understanding electric fields and potentials in cylindrical geometries.

Richard Ros
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An infinitely long solid insulating cylinder of radius a = 5.2 cm is positioned with its symmetry axis along the z-axis as shown. The cylinder is uniformly charged with a charge density ρ = 23 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 14.2 cm, and outer radius c = 16.2 cm. The conducting shell has a linear charge density λ = -0.45μC/m.

1. What is Ey(R), the y-component of the electric field at point R, located a distance d = 58 cm from the origin along the y-axis as shown?
-7897.28N/C

2. What's V(c)-v(a), the potential difference between the outer surface of the conductor and the outer surface of the insulator.
KQ
My Attempt : Vc - Va = kq/c - kq/a
vc - va = qk * (1/c - 1/a)
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
First find the E field using a gaussian surface, then integrate E from the cylinder to the shell.
 

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