- #1

LCSphysicist

- 646

- 162

- Homework Statement
- I.

- Relevant Equations
- .

I am passing through some difficulties to understand the reasoning to derive the electric potential of an oscilating dipole used by Griffths at his Electrodynamics book:

Knowing that ##t_o = t - r/c##,

What exactly he has used here to go from the first term after "and hence" to the second term? (The one involving ##\ddot p##). Maybe ##\nabla = \nabla t_o \frac{d}{dt_o}## ? But this does not make sense.

Knowing that ##t_o = t - r/c##,

What exactly he has used here to go from the first term after "and hence" to the second term? (The one involving ##\ddot p##). Maybe ##\nabla = \nabla t_o \frac{d}{dt_o}## ? But this does not make sense.