Power associated with net force

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Homework Help Overview

The discussion revolves around the relationship between power and net force, specifically the equation P*F_net = (dK)/(dt), which expresses power associated with net force as the rate of change of kinetic energy. Participants are examining the definitions and implications of this equation within the context of physics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of power and its relation to work and force. There is a focus on whether the equation is dimensionally correct and how to interpret the terms involved. Some participants clarify the notation used in the equation, indicating a misunderstanding regarding the product of force and power.

Discussion Status

The discussion is progressing with participants clarifying notation and addressing dimensional concerns. There is an indication that some participants are moving towards a resolution, with one suggesting that the answer is close at hand.

Contextual Notes

Assumptions about constant force and acceleration are mentioned, and there is a lack of explicit questions regarding the system or forces involved, which may limit the depth of exploration.

REVIANNA
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Homework Statement



How to prove :
[/B]
##P*F_net=((dK)/(dt))##
i.e. power associated with the net force is the rate of change of kinetic energy.

The Attempt at a Solution


[/B]
if I use the definition of power ans then that of work I get (m*a*ΔS )*(F_net)
further using F_net=ma
LHS= ##m^2*a^2*ΔS##

There is no question along with it for which I could have though about the system and forces.
so I am assuming const force and acceleration.
 
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REVIANNA said:
P∗Fnet=((dK)/(dt))P*F_net=((dK)/(dt))
Is that product of force and power on LHS? If yes, the equation looks dimensionally incorrect.
Actually, if you solved dK/dt first, you'll get power.
 
Last edited:
cnh1995 said:
Is that product of force and power on LHS? If yes, the equation looks dimensionally incorrect.
Actually, if you solved dK/dt first, you'll get power.

so sorry ,actually the F_net was written as the subscript P ,not their product
this makes complete sense now
##P_F=(dK/dt)##
 
REVIANNA said:
so sorry ,actually the F_net was written as the subscript P which not their product
this makes complete sense now
##P_F=(dK/dt)##
Then I believe answer is a couple of steps away. Good luck..
 
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