Power of 4: Last Digit Analysis

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Homework Help Overview

The discussion revolves around analyzing the last digit of n^4, where n is a natural number. Participants explore the potential last digits of n^4, specifically focusing on the digits zero, one, five, or six.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants consider various methods, including case analysis and direct proof. Questions arise about the effectiveness of these approaches and the reasoning behind them.

Discussion Status

The discussion is active, with participants sharing different strategies and questioning the validity of their approaches. Some are exploring the implications of odd and even numbers in their reasoning.

Contextual Notes

There is an emphasis on understanding the relationship between n and its fourth power, particularly regarding how the last digit is determined. Participants are also considering the implications of different representations of n.

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Homework Statement



If n is a natural number, then n^4 ends in either zero, one, five, or six.

Homework Equations





The Attempt at a Solution



Should I attempt this by cases?
 
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dainty77 said:
Should I attempt this by cases?

What cases did you have in mind? Why don't you show us what you are thinking.
 
Actually not cases, but by a direct proof so:

let n^4=(n^2)^2
Let n be an odd number
Then n=2k+1 for some integer k
then n^2= (2k+1)^2
=4k^2 + 4k +1
=2(2k^2+2k) + 1

I don't think this is proving anything. I will try something else
 
Let n = 10m + k

Where m and k are naturals and k lies in the interval [0,9].

Take the 4th power of this expression. Can you find the term responsible for the final digit of n^4? Why is it responsible for the final digit? What are its possible values?
 
Last edited:

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