Power of a car, time distance speed mass

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Homework Help Overview

The problem involves calculating the power of a car given its mass, time to reach a certain speed, and the speed itself. The context includes concepts from mechanics such as force, acceleration, work, and power.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss different methods to calculate power, including using force and work. There are attempts to clarify the definitions of average versus instantaneous power, and questions arise regarding the correct distance traveled during acceleration.

Discussion Status

Some participants have provided calculations leading to different power values, with one asserting that the book's answer is correct. There is ongoing exploration of the relationship between acceleration, distance, and power, with hints towards finding average power rather than instantaneous values.

Contextual Notes

There is a noted discrepancy regarding the distance calculation, with participants questioning the assumptions made about average speed and the definitions used in the problem.

abruski
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Homework Statement



A car with mass m = 1 metric ton (1000 kg) in time t = 5 seconds reaches speed v = 20 m/s

What is the power of the car? P = ? kW (kilo Watts)

Homework Equations



F - force, a - acceleration, A - work, s - distance

P = \frac{A}{t}

P = Fv

F = ma

a = \frac{v}{t}

A = Fs

s = vt

The Attempt at a Solution



The answer given in the book is 40 kW but I get 80 kW. With the 40 kW I get that the acceleration s 2 m/s^{2}, which means that
\frac{v}{t} = \frac{20}{5} = 2

??

Maybe I miss something. Any help is appreciated.
 
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abruski said:
The answer given in the book is 40 kW but I get 80 kW.
Show how you got your answer. Hint: Find the average power.
 
a = \frac{v}{t} = \frac{20}{5} = 4 \frac{m}{s^{2}}

s = vt = 100 m

F = ma = 1000*4 = 4000 N

A = Fs = 4000*100 = 400000 J


P = Fv = 4000*20 = 80 000 W

P = \frac{A}{t} = \frac{400000}{5} = 80 000 W

seems pretty straightforward to me
 
40 kW is a correct answer.

Distance is not 100 m.

While the final answer should be identical no matter how you solve the question, comparing final energy of the car with the work done seems to be much easier approach.
 
how come distance is not 100m?
 
20 m/s is a FINAL speed, not average.
 
What about the acceleration?
 
abruski said:
What about the acceleration?
What about it? Realize that the instantaneous power varies throughout the motion. You want the average power. Rather than mess around with kinematics, use the most basic definition of power as energy/time.
 

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