Power required to climb a 20-m-tall building in 55s

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SUMMARY

A 90 kg firefighter carrying 40 kg of gear must climb a 20-meter tall building in 55 seconds, resulting in a total mass of 130 kg. The potential energy at the top, calculated using the formula U = mgy, equals 25,480 Joules. Dividing this energy by the time of 55 seconds yields a power requirement of 463 Watts. This calculation assumes perfect efficiency, acknowledging that real-world conditions will result in energy loss to thermal energy.

PREREQUISITES
  • Understanding of potential energy calculations (U = mgy)
  • Basic knowledge of power calculations (Power = Energy / Time)
  • Familiarity with mass and weight concepts
  • Awareness of energy efficiency principles
NEXT STEPS
  • Research the effects of thermal energy loss in physical exertion
  • Explore the physics of climbing and energy expenditure in firefighting
  • Learn about the impact of gear weight on physical performance
  • Investigate methods to improve energy efficiency during strenuous activities
USEFUL FOR

Firefighters, exercise physiologists, sports scientists, and anyone interested in the physics of climbing and energy expenditure in physical activities.

ChetBarkley
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Summary:: A 90 kg firefighter needs to climb the stairs of a 20-m-tall building while carrying 40kg of gear. How much power does he need to reach the top of the building in 55s.

So first the total mass of our system is 130 kg. Using this mass, I found the potential energy the firefighter would have at the top of the building. Using U = mgy, I got 25480 J then knowing that power is just Jules over time I divided this by 55s and got 463 Watts. Is this correct?
 
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Looks good to me. That assumes perfect efficiency, but that's OK. In real life, much of the work done by the firefighter will go to thermal energy.
 
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