Power Series ArcTan: Analyzing the Expansion & Convergence

sammiekurr
Messages
2
Reaction score
0
Power Series ArcTan?

Homework Statement


Let f be the function given by f(t) = 4/(1+t^2) and G be the function given by G(x)= Integral from 0 to x of f(t)dt.
A) Find the first four nonzero terms and the general term for the power series expansion of f(t) about x=0.
B) Find the first four nonzero terms and the general term for the power series expansion of G(t) about x=0.
C) Find the interval of convergence of the power series in part (B). Show the analysis that leads to your conclusion.


Homework Equations


d/dtArctan(t)=1/(1+t^2)


The Attempt at a Solution


A) a=4, R=-t^2. f(t)=Sum from n=1 to infinity of 4 * (-1)^n * t^2n
First four terms: -4t^2 + 4t^4 - 4t^6 + 4t^8

B) Integral from 0 to x of 4/(1+t^2)dt = 4arctan(t) from 0 to x = 4arctan(x)

Now I don't know where to go from here. I don't know how to write the power series for the antiderivative of the original power series, since it is not in the standard form of a power series. Can anybody help?
 
Physics news on Phys.org


sammiekurr said:

Homework Statement


Let f be the function given by f(t) = 4/(1+t^2) and G be the function given by G(x)= Integral from 0 to x of f(t)dt.
A) Find the first four nonzero terms and the general term for the power series expansion of f(t) about x=0.
B) Find the first four nonzero terms and the general term for the power series expansion of G(t) about x=0.
C) Find the interval of convergence of the power series in part (B). Show the analysis that leads to your conclusion.


Homework Equations


d/dtArctan(t)=1/(1+t^2)


The Attempt at a Solution


A) a=4, R=-t^2. f(t)=Sum from n=1 to infinity of 4 * (-1)^n * t^2n
First four terms: -4t^2 + 4t^4 - 4t^6 + 4t^8
No. You have the formula right but when n= 0, 4(-1)^n t^2n is 4. The first four terms are 4- 4t^2+ 4t^4- 4t^6.

B) Integral from 0 to x of 4/(1+t^2)dt = 4arctan(t) from 0 to x = 4arctan(x)

Now I don't know where to go from here. I don't know how to write the power series for the antiderivative of the original power series, since it is not in the standard form of a power series. Can anybody help?
Why is it "not in the standard form of a power series"?

You have that 4/(1+ t^2)= 4\sum_{n=0}^\infty (-1)^n t^{2n} and can integrate "term by term".
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top