Power series for complex function

Pyroadept
Messages
82
Reaction score
0

Homework Statement


Find the power series for the function
f(z) = (1-z)^-m

Hint: Differentiation gives:
f'(z) = m(1-z)^m-1
= m(1-z)^-1.f(z)

or:
zf'(z) + mf(z) = f'(z)

Use the formula for differentiation of power series to determine the coefficients of the power series for f.


Homework Equations





The Attempt at a Solution



Hi, here's my attempt so far:

From real analysis,
(1-x)^-1 = Σ(a_n).x^n, where the sum is from n=0 to infinity

Differentiating:f'(x) (1-x)^-2 = Σ(a_n).n.(x^n-1) , from n=0 to infinity

and so on until we get that the j-th derivative

i.e. f^j.(x) = Σa_n(n C j).(x^n-j), where (n C j) is "n choose j" (binomial coefficient.

Thus, substituting z for x and m for j,

(1-x)^-m = Σa_n(n C m).(x^n-m), sum from 0 to infinity.


---

I don't think this is correct; it seems too straightforward and I haven't used the hint.
Can someone please point me in the right direction?

Thanks for any help!
 
Physics news on Phys.org
... not to mention that you still have an infinite number of undetermined coefficients.

They give you a first order ODE. Solve it using power series.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top