Power Series- radius of convergence

Roni1985
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Homework Statement


determine the radius of convergence of the given power series

\sum^{inf}_{n=1}\frac{n!x^n}{n^n}

Homework Equations





The Attempt at a Solution


I did the ratio test
then I had to take the 'ln'
but, my answer is this
|e|<1 for the series to converge.
It never happens but according to the answers the radius is 'e'.
 
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oh I think I got it, I didn't have to lhopital lnx in the middle ...
:\
 
Applying the Ratio Test, we have the sequence

\frac{(n+1)n^n}{(n+1)^{(n+1)}} = \left(\frac{n}{n+1}\right)^n = \left(\frac{1}{1 + \frac{1}{n}}\right)^n

Taking the limit as n goes to infinity... this might look like a familiar limit. Then recall that the Radius of convergence is the reciprocal of this limit.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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