Power series representation of 10xarctan(5x).

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SUMMARY

The function f(x) = 10x arctan(5x) can be represented as a power series by substituting 5x into the known series for arctan(x). The correct representation yields the series summation from n=0 to infinity of (-1)^n (10x)(5x)^(2n+1)/(2n+1), resulting in the first few coefficients: 50, 0, 250/3, 0, and -10/5. The multiplication by 10x is valid and necessary for deriving the coefficients of the power series.

PREREQUISITES
  • Understanding of power series representation
  • Familiarity with the arctan function and its series expansion
  • Basic algebraic manipulation of series
  • Knowledge of coefficient extraction from series
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  • Study the derivation of power series for other functions, such as sin(x) and cos(x)
  • Learn about convergence criteria for power series
  • Explore the application of Taylor series in calculus
  • Investigate the use of symbolic computation tools like Mathematica for series expansion
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Students studying calculus, particularly those focusing on series expansions, and educators looking to clarify power series concepts in their teaching.

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Homework Statement



The function f(x)=10xarctan(5x) is represented as a power series
http://img464.imageshack.us/img464/4131/formub5.jpg
Find the first few(5) coefficients in the power series.

Homework Equations



I already know that the representation of arctanx is summation from n=0 to infinity of (-1)^n x^(2n+1)/(2n+1).

The Attempt at a Solution



So I plugged in 5x and then multiplied the entire thing by 10x.

I ended up with summation n=0 to infinity (-1)^n (10x)(5x)^2n+1/(2n+1) = 50x^2 + 10x(5x)^3/3-10x(5x)^5/5+...

I've asked a few people, and while they don't seem to remember power series very well, the only issue they could point out is that you can't multiply the whole thing by 10x. Is that true? If it is... then how do I go about solving this?
 
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Perhaps those few people remember even less than they thought. Because you certainly can do that.
 

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