Power, the rate of energy transfer

AI Thread Summary
A 613.0 kg mass is being lifted by a forklift with a power output of 950 W, and the discussion revolves around calculating the constant speed of the forklift. Participants emphasize the need to understand the relationship between power, work, and force, with the equation P = dW/dt being central to the solution. The force due to gravity (Fg) is calculated as 6007 N, and participants explore how to derive velocity from power and force. There is confusion regarding the calculations, with one participant mistakenly suggesting an unrealistically high speed of 950 m/s before correcting to 0.158 m/s. The conversation highlights the importance of correctly applying physics equations to solve for velocity in this context.
dbigtheory
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Homework Statement


A 613.0 kg mass is placed on a forklift that can generate 950 W of power. What is the constant speed of the forklift while lifting this load?


Homework Equations


P= E/T
e=energy in joules
T= time

The Attempt at a Solution


not enough information therefore i couldn't do it. pls help
 
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dbigtheory said:

Homework Statement


A 613.0 kg mass is placed on a forklift that can generate 950 W of power. What is the constant speed of the forklift while lifting this load?


Homework Equations


P= E/T
e=energy in joules
T= time

The Attempt at a Solution


not enough information therefore i couldn't do it. pls help

Hint: P = \frac{dW}{dt}

Where W is the work.
 
time and work are not given, only have Watt and i have no idea wat to do with Kg and i need to find velocity...dunno
 
dbigtheory said:
time and work are not given, only have Watt and i have no idea wat to do with Kg and i need to find velocity...dunno

What is the equation for the work done in this problem?
 
W= FD but i don't have the distance
 
dbigtheory said:
W= FD but i don't have the distance

Right, and what is F?
 
Watt, power
 
No, F is the force doing the work W = FD, what force is doing the work?
 
i know what you're getting into but i have try that attempt before, even so I don't understand how to find the velocity with FG
 
  • #10
I'm trying to help you lol. If you knew what I was getting at you would already have the answer. You know what W is so what is dW/dt?
 
  • #11
velocity but i don't have the time?
 
  • #12
Would you please show your work. I cannot help you otherwise. Show what you have done. W is work not velocity.
 
  • #13
ok i think i get it you divide the FG by the power to find time and then divide the Fg by the time>? i think
 
  • #14
dbigtheory said:
ok i think i get it you divide the FG by the power to find time and then divide the Fg by the time>? i think

UGH. PLEASE WRITE EQUATIONS. Let's start over, this is not that difficult you can do it I promise, but I don't want to just give you the answer. You know derivatives right?

P = \frac{dW}{dt}

Where W is the work done. So power is the rate of change of work with respect to time. So if you can write out the equation for work then all you have to do is take the derivative of it (dw/dt) and that will be equal to the power.
 
  • #15
so 950w= 6007N/dt and then i use it to find time and i know velocity?
 
  • #16
dbigtheory said:
so 950w= 6007N/dt and then i use it to find time and i know velocity?

W = F_g x = mgx

What is dW/dt?
 
  • #17
velocity, i got 950m/s. i got the time by dividing dw by P. i think tis should be right
 
  • #18
yo man don't worry i about it. i screwed up, the answer suppose to be 0. 158m/s. thanks for your help though
 
  • #19
dbigtheory said:
velocity, i got 950m/s. i got the time by dividing dw by P. i think tis should be right

That is 2000 mph! DO YOU KNOW DERIVATIVES?? This is what you are going to do:

FIND dw/dt (W = mgx) where x is the change in height and POST WHAT YOU GET FOR THE DERIVATIVE.
 
  • #20
Remember mg is a constant, but x is not.
 
  • #21
Grazie!
 
  • #22
No problem
 

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